What is the slope of a line that is perpendicular to the line whose equation is 3x+2y=6?

first, we can find the slope from the equation that is given buy solving the equation for y

3x+2y = 6

2y = 6-3x

y = 3-3/2x

y = -3/2x+3

now that the equation is in slope-intercept form, we can easily see that the slope of the given line is -3/2

perpendicular lines have slopes that are negative reciprocals, so we can just take the negative reciprocal of the slope we have

-3/2 → 3/2 → 2/3

the slope of the perpendicular line is 2/3

hope this helped

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)

there is only one way to arrange all the eight relative to each other because they are not distinct. we have

now there are nine places to place an (and not more than one in one place).   because we have four symbols, we need to choose four of these nine places to insert an . order does not matter because the are not distinct.

thus there are 1 · c(9,4) ways, or, if we calculate it,

thus there are 126 ways to form such "words."