Find the approximate area of a triangle that has vertices at a(-4,-2) b(1,1) and c(5, -1). 14 square units 18 square units 20 square units 22 square units

using the formula 1/2(b*h) you should get 13.5 so approximately 14

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i