What is the probability of flipping a fair coin and having 4 consecutive heads? a. 1/8 b. 1/16 c. 1/2 d. 1/6

Let X be the event of getting head on flip of a fair coin. As the coin is fair the probability of getting head or tail is same which is 1/2.

Now probability of getting 4 consecutive heads

P(4 consecutive heads) = P(head on first flip) * P(head on second flip) * P(head on third flip) * P(head on fourth flip)

= (1/2) * (1/2) * (1/2) * (1/2)

= 1/16

The probability of getting head on four consecutive flips is B. 1/16

so what is the question

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