Aladder is leaning against a building. the distance from the bottom of the ladder to the building is 16 ft less than the length of the ladder. how high up the side of the building is the top of the ladder if that distance is 2 ft less than the length of the ladder?

Let's say the length of the ladder is "d". Since the distance from the bottom of the ladder to the building is 16 feet less than the length, we can write this as d - 16.

The distance from the ground to the top of the ladder is 2 feet less than the length of the ladder, so we can denote this as

d - 2.

The shape made by the ground, ladder, and side of the building is a right triangle, and we just found its legs. We can use the Pythagorean Theorem to solve for "d" and find how far up the side of the building the ladder is:

(d - 16)^2 + (d - 2)^2 = d^2

(d^2 - 32d + 256) + (d^2 - 4d + 4) = d^2

2d^2 - 36d + 260 = d^2

d^2 - 36d + 260 = 0

(d - 26) * (d - 10) = 0

d = 26 or d = 10

The answer d = 10 does not fit in this case because it isn't possible to have 16 feet less of 10 feet; it would be negative!

So, d = 26. The top of the ladder to the ground is 2 less than d, so we do 26 - 2 = 24 feet.

The answer is 24 feet.

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: