The work of a student to solve the equation 2(4x − 4) = 8 + 4x + 4 is shown below: step 1. 2(4x − 4) = 8 + 4x + 4 step 2. 6x − 6 = 12 + 4x step 3. 6x − 4x = 12 + 6 step 4. 2x = 18 step 5. x = 9 in which step did the student first make an error and what is the correct step? step 2, 8x − 6 = 2(6 + 2x + 2) step 2, 8x − 8 = 12 + 4x step 3, 6x − 4x = 12 − 6 step 3, 6x + 4x = 12 + 6

Answer is step 2, 8x - 8= 12 + 4x

The student did not distribute the 2 into the parentheses properly which ruined their entire problem. With 2(4x-4) , you must multiply everything in parentheses by 2.

so 2 x 4x = 8x

2 x -4 = -8

making it 8x- 8 = 12 + 4x ( on the right side all you did was combine like terms)

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!