Solve x2 − 8x + 5 = 0 using the completing-the-square method.

First, let's move the 5 to the other side by subtracting both sides by 5. That leaves us with:

x^2 - 8x = -5

The constant on the left side to make a binomial square should be (8/2)^2 = 16. Add 16 to both sides and you get: x^2 - 8x + 16 = 11

(x - 4)^2 = 11

Square root both sides:

(x - 4) = +/- sqrt (11)

Add 4 to both sides:

x = +/- sqrt (11) + 4

The 4 should be outside the square root.

17.08

correct me if i am wrong.

both graphs increase on their domain

neither graph has a y-intercept

step-by-step explanation:

the following points can be visualized easily from the graph