Find two consecutive odd integers such that thier product is 143 more than 5 times their sum

Let one number be x

The other number is x + 2

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their product is 143 more than 5 times their sums:

x (x + 2) = 5 (x + (x + 2) ) + 143

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Solve x:

x (x + 2) = 5 (x + (x + 2) ) + 143

x(x + 2) = 5 (2x + 2) + 143

x² + 2x = 10x + 10 + 143

x² - 8x - 153 = 0

(x + 9) (x - 17) = 0

x = - 9 or x = 17

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When x = - 9

1st number = -9

2nd number = - 9 + 2 = -7

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When x = 17

1st number = 17

2nd number = 17 + 2 = 19

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The two numbers are -7 and -9 or 17 and 19

b) 36

step-by-step explanation:

18 times 2 is 36

hi,

i'm 75% sure the answer is 1,1 to both lines.

have a great day