Assume that the speed of automobiles on an expressway during rush hour is normally distributed with a mean of 63 mph and a standard deviation of 10 mph. what percent of cars are traveling faster than 79 mph?

The speed is normally distributed with mean μ=63 and standard deviation σ =10.

Use the transformation for calculating the probability. This value is called Z-score.

The Z score is .

Refer to the standard normal distribution table.

The probability

Thus, of the cars are travelling faster than 79 mph.

2 x^2 -3x+p

sum of roots = 3/2

let other root be x

3+ x = 3/2

x= 3/2 - 3 = -3/2

product of roots = p/2

3× -3/2 = p/2

-9 = p

⭐⭐

x=17

step-by-step explanation:

solve 3x-24=x+10

then that makes it 2x=34 because you subtract an x from both sides to get rid of the one on the right, and then you add 24 to both sides to get rid of the 24 on the left

divide by both sides by 2 to get your answer so that you can get your answer