The projected worth (in millions of dollars) of a larger company is modeled by the equation w=241(1.06)t. the variable t represent the number of years since 2000. what is the project annual percent of growth, and what should the be worth in 2001?

The equation is

And here variable t represents the number of years since 2000.

In 2001 means t=2001 -2000 = 1

So we plug 1 for t in the given expression , that is

Therefore in 2001, it should be worth to 255.46.

And in the given expression 1.06=1 +0.06, where 0.06 is the annual percent of growth that is 6 % .

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.

the answer to this question is 3/19

step-by-step explanation: