Asquare abcd has the vertices a(n, n), b(n, -n), c(-n, -n), and d(-n, n). which vertex is in quadrant iii? b c a d

It is necessary for a coordinate to be in quadrant III that both x and y coordinate have to be negative. For e.g (-2,-2) have both x and y coordinate negative , so it is in quadrant III , where as (2,-2) or(-2,2) are not in quadrant III. In the given question C (-a,-a) have both x and y coordinates negative. SO C is in third quadrant and the correct option is C .

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

sas (side angle side)

aa(angle angle)

sss(side side side)

sas you have to find two sides with an angle in between

aa you find two angles because it will always add up to 180

sss find all sides

step-by-step explanation: