Jules kicks a soccer ball off the ground and into the air with an initial velocity of 25 feet per second. assume the starting height of the ball is 0 feet. approximateley what maximum height does the soccer ball reach.

Use the formula h(t) = -16t^2 + vt + s,

where t = time in air,

v = starting upward velocity,

s = the objects starting height.

from ground (s), the starting height is 0,

the ball's initial velocity (v) 25 feet per second

Solve:

v - 16t^2 + (25)t + 0

= -16t^2 + 25t. 0

Factor:

= -16t^2 + 25t

Find GCF:

0 = -16t^2 + 25t

Divide both sides by (t)

t(-16 + 25) = 0

t = 0; -16 + 25 = 0

Now Subtract 25 from both sides of equation:

-16 = -25

divide both sides by -16 to get -25/-16

= 1.56

Rounds to 1.60, or 1.6

1.6 Seconds it will take for soccer ball to hit the ground again.

First part of the Equation: 9.8Ft. Soccer ball will reach at maximum height.

Hope that helps : )

i need the table so i can see

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