Write 9^0 , 9^3, and 9^-2 in order least to greatest

The order is 9^-2, 9^0, 9^3.

When an exponent is negative, the term can be moved from the numinator to the denominator (or vise versa) to change the negative exponent to a positive one. So 9^-2 becomes 1/9^2 = 1/81.

Anything to the 0th power becomes 1. So 9^0 is 1.

Finally, 9^3 is 729.

the solution of the equation is 2.23 ⇒ answer b

step-by-step explanation:

* lets revise the meaning of exponential function

- the form of the exponential function is y = ab^x, where a ≠ 0, b > 0 ,  

  b ≠ 1, and x is any real number

- it has a constant base b

- it has a variable exponent x

- to solve an exponential equation, take the log or ln of both sides,  

  and solve for the variable

* lets solve the problem

∵

- the base is 7 and the exponent is x

- insert ㏑ in both sides

∴

- use the rule

∴ x ㏑(7) = ㏑(77)

- to find x divide both sides by ㏑(7)

∴

* the solution of the equation is 2.23 to the nearest 2 decimal places