State the possible number of positive real zeros, negative real zeros, and imaginary zeros f(x)=-x^3-x^2+14x-24

Examine the number of sign changes for f(x) and f(-x)

There are two sign changes for the coefficient of f(x), so the function has 2 or 0 positive real zeros.

There is 1 sign change for the coefficients of f(-x). So f(x) has one negative real zero.

Thus, f(x) has 2 or 0 positive real zeros, 1 negative real zero, 2 or 4 imaginary zeros

answer: $34.31

step-by-step explanation:

$11.99 x 3 = $35.97

$35.97 - 10% = $32.37

$32.37 + 6% = $34.31