98 points brainliest ! a ball is thrown from the top of a building. the function below shows the height of the ball in relation to sea level, f(t), in feet, at different times, t, in seconds: f(t) = -16t^2 + 32t + 90 the average rate of f(t) from t = 4 and t = 6 seconds is seconds. i think the answer is -128 ft per second. if that's right let me know and if it's not explain what you did.

The height of the ball as a function of t is given

f(t)=-16*t^2+32t+90

The velocity is the derivative of f(t) with respect to time (using calculus)

v(t)=f'(t)=-32t+32

(if you have not done calculus before, then use the kinematic equation

v(t)=v0+at=32-32t (given v0=initial velocity=32 ft/s, acceleration due to gravity=-32 ft/s^2)

The average velocity between t1 and t2 is given by

v=(v(t2)+v(t1))/(t2-t1),

Substituting t2=6 s., t1=4 s.

v=(v(6)+v(4))/(6-4)=(-160+(-96))/2=-256/2=-128

Therefore

your answer of -128 ft per second is correct.

Hello!

I believe you are correct, the answer is -128 fps.

I hope it helps!

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