Write the expression as a single logarithm

1/2 [3logx + logy]

Step 1:

we use the property of n logx =log xⁿ for 3 logx

so 1/2[3logx +logy]= 1/2 [log x³ + log y]

Step 2:

We use another property here log a + log b = log (ab)

1/2[log x³y]

Step 3:

we again use the property of n logx =log xⁿ, bringing 1/2 in power

[log x³y]^1/2

√log(x³y)

i dont know i just need points

"image"

step-by-step explanation:

in most of these problems, the notation is that the point with a "prime" is the image of the point without. that is, b' is the image of b.

here, there is no dilation or reflection. there is simply translation (with no direction shown). which figure you call the "preimage" and which one you call the "image" is up to you. as a matter of convention, the naming is as described above.