In a state's pick 3 lottery game, you pay $1.33 to select a sequence of three digits (from 0 to 9), such as 288. if you select the same sequence of three digits that are drawn, you win and collect $384.13.

A. How many different selections are possible?

B. What is the probability of winning?

C. If you win, what is your net profit?

D. Find the expected value

Answer :

A. sequence of three digits (from 0 to 9). so 10 numbers.

We know 3 lottery games. So possible selections = 10^3 = 1000

B. Probability of winning = one outcome / total outcomes

P( winning) = = 0.001

c. Net profit = winning amount - paid amount

= 384.13 - 1.33 = $382.8

D. expected value

E(x) = net profit * winning probability - paid amount * lost probability

E(x) = 382.8 * 0.001 - 1.33 * 0.999 = -0.95

you expect to lose 95 cents per ticket.

3/4 ÷ 3/4

step-by-step explanation:

basically divide any proper fraction with itself to fit the criteria.

so if we are using 3/4, then:

3/4 ÷ 3/4 = 1

so 1 is the quotient.

and the numerators for both these fractions is 3.   and if we divide the numerators:

3 ÷ 3 = 1

we see that quotient is equal to our original quotient as well.

yes

step-by-step explanation:

yes