Three consecutive whole numbers add to 57 what are the numbets

Suppose that three consecutive whole numbers are :

First number = x

Second Number = x+1

Third Number = x+2

Given that sum of 3 numbers is 57

x + (x + 1) + (x + 2) = 57

x + x + 1 + x + 2 = 57

3x + 3 = 57

3x = 54

x = 18

So, first whole number x = 18

second whole number = x+1 = 18 + 1 = 19

third whole number = x +2 = 18 + 2 = 20

Final answer is : 18, 19, 20

x + x + 1 + x + 2 = 57

3x + 3 = 57

3x = 54

x = 18

So the numbers are 18, 19 and 20.

answer: 42

use a calculator to find that 845/73 = 11.575

the whole part of the answer is 11. multiply this by 73 to get 11*73 = 803.

subtract that result from 845 to get 845 - 803 = 42

a) 7x=7

step-by-step explanation: