What is the sum of a 58th arithmetic sequence where the first term is 6 and the last term is 405

Formula to find the sum of nth terms of an arithmetic sequence is:

Where, = sum of nth terms.

= first term.

= last term.

Now we need to find, sum of a 58th arithmetic sequence where the first term is 6 and the last term is 405 .

So, plug in n = 58, = 6 and = 405 in the above formula.

=

=

= 11919

So, the sum of 58th terms is 11919.

Hope this helps you!.

for finding the midpoint of any given 2 pair of points simply add the respective x coordinates with other x coordinate and the y coordinate with other y coordinate and divide them by 2

in your question it will be :

(3+1)/2 for the x coordinate of mid point i.e 2

[8+(-4)]/2 for the y coordinate of midpoint i.e 2

so coordinates of mid point of points (3,8) and (1,-4) will be (2,2)

y=-2.5x+12.5

step-by-step explanation:

5y=2x+10

y=0.4x+2

slope=-2.5

5=-2.5*3+b

b=12.5