Ayouth organization collected nickels and dimes for a charity drive. by the end of the 1-day drive, the youth had collected $63.80. if there were five times as many dimes as nickels how many of each type of coin was collected

Let, the numbers of nickels be x.

Given, there were 5 times as many dimes as nickels.

So, the number of dimes = 5x

We know that 1 nickel = $(0.05)

So x nickels = $(0.05x)

Also we know that 1 dime = $(0.1)

So 5x dimes = $(0.1 ×5x) = $(0.5x)

Given total value of dimes and nickels at the end of day 1 is $63.80

So we can write the equation

Now we to find x, we have to move 0.55 to the other side. As 0.55 is multiplied there so to move it we need to divide it to both sides.

So we have got the number of nickels = 116

Number of dimes = 5x = 5(116) = 580

So we have got the required answer.

Number of nickels = 116, number of dimes = 580.

22, 28, 34, 40, 46

b)   f(n) = 6n + 16

n = what is the number of the row ( 22 would be row 1) so if we replaced n with 1, we would get 22

c)   the 14th row will have 100 seats

(1)   (2)   (3)   (4)   (5)   (6)   (7)   (8)   (9)   (10) (11) (12) (13) (14)

22 | 28 | 34 | 40 | 46 | 52 | 58 | 64 | 70 | 76 | 82 | 88 | 94 | 100