What are the amplitude, period, phase shift, and midline of f(x) = −4 cos(3x − π) + 1? amplitude: −4; period: pi over 3; phase shift: x = pi over 4; midline: y = −1 amplitude: 4; period: pi over 3; phase shift: x = pi over 4; midline: y = 1 amplitude: −4; period: 2 pi over 3; phase shift: x = pi over 3; midline: y = −1 amplitude: 4; period: 2 pi over 3; phase shift: x = pi over 3; midline: y = 1?

Alright, lets get started.

The standard form for cos function is

Where

A = Amplitude (positive value)

Period =

Phase shift =

Mid line or vertical shift = D

So, comparing the given function with standard

A = 4

B = 3

C=

D = 1

Means Amplitude = 4

Period =

Phase shift =

Mid line = 1

Hence the answer is last choice 4.

Hope it will help :)

x = 2

step-by-step explanation:

if sr parallel to ba then the sides bc and ac are in proportion, that is

= ← substitute values

= ( cross- multiply )

27x = 6(4x + 1)

27x = 24x + 6 ( subtract 24x from both sides )

3x = 6 ( divide both sides by 3 )

x = 2

mrbilldoesmath!

answer: a parabola

steps:

(x-1)(x+4)   = x(x+4) - 1(x+4) = (x^2 + 4x) - (x+4)

                = x^2 +4x -x -4   = x^2 +3x -4

which is a parabola

mrb