find bc. round to the nearest tenth. a. 19.1 b. 20.8 c. 23.1 d. 23.3

We can use the sine rule for this problem.

Sine rule formula is:

Where a (side BC), b (side AC) and c (side AB) are the opposite sides of the angle A, B and C repectively.

According to the given figure,

B= 79°, C = 30° and AB= c =11 and we need to find side BC= a.

Hence, first step is to find the angle A.

Sum of all angles of a triangle is 180°.

So, ∠A +∠B + ∠C = 180.

∠A + 79 + 30 = 180

∠A + 109 = 180

∠A = 180 - 109

∠A = 71°.

So, let's use the formula:

So, a = 20.801

Therefor BC is 20.8 ( Rounded to nearest tenth).

"Hope this helps!!"

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752

answer: 270

step-by-step explanation:

you have to times 200 by 1.35 to get your answer