When using the inspection method to rewrite the rational expression x^2-10x+14/x-8 , what constant term must the numerator have for to be one of its factors? what number must you add to (and subtract from) the numerator's constant term to derive (x-8) as a factor? for the numerator to have (x-8) as a factor, its constant term must be . to get this number, add and subtract from the numerator’s constant term.

General idea:

When we factor a trinomial of the form , we need two numbers m and n to write it as product of two binomials like, where .

In order to get two numbers we need to list the factor pairs of c and see which two factors add up to give b.

Applying the concept:

We need to make alterations to the constant term in such a way that below equation is true.

Conclusion:

Right now the numerator is , we need to add 2 to the constant of the numerator expression to get .

For the numerator to have (x-8) as a factor, its constant term must be 16 .

area = length x width

length = 2 x width

32 = 2 x width x width

32 = 2 x width^2

36 = width ^2  

width = 6

length = 12

area is 32

perimeter = 2 x 12 + 2 x 6 = 24 + 12 = 36

step-by-step explanation: