One side of a triangle is half the longest side the third side is 10 feet less than the longest side the perimeter is 70 find all three sides

Let the longest side of the triangle be x, then the length of one of the other sides of the triangle is 0.5x and the length of the third side is x - 10.

Then, x + 0.5x + x - 10 = 70

2.5x = 80

x = 80 / 2.5 = 32

Therefore, the length of the sides of the triangle are: 32, 0.5(32) = 16 and 32 - 10 = 22.

i.e. 32, 16, 22

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !