What is the orthocenter of a triangle with vertices a(−3,−2)a(−3,−2), b(−2,2)b(−2,2), and c(2,−2)c(2,−2)?

A(−3,−2), B(−2,2), C(2,−2)

The orthocenter is the meet of the altitudes. We see AC is parallel to the x axis so the perpendicular is the altitude through B.

Between A and B we have slope (2 - -2)/(-2 - -3) = 4 so perpendicular slope -1/4 through C(2,-2):

For the y coordinate of the orthocenter we substitute in x=-2.

So the orthocenter is (x,y)=(-2,-1)

(-2,-1)

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

answer: 193

explanation:

200-7 = 193