You're a manager in a company that produces rocket ships. machine a and machine b both produce cockpits and propulsion systems. machine a and machine b produce cockpits at the same rate, and they produce propulsion systems at the same rate. machine a ran for 26 hours and produced 4 cockpits and 6 propulsion systems. machine b ran for 56 hours and produced 8 cockpits and 12 propulsion systems. we use a system of linear equations in two variables. can we solve for a unique amount of time that it takes each machine to produce a cockpit and to produce a propulsion system?

No you cannot.

Step-by-step explanation:

Let c be the amount of time it takes each machine to make 1 cockpit, and p be the amount of time it takes each machine to make 1 propulsion system.

For Machine A, we have 4 cockpits; this would take 4c time.  We also have 6 propulsion systems; this would take 6p time.  Together it takes 26 hours; this would give us

4c+6p=26.

For Machine B, we have 8 cockpits; this would take 8c time.  We also have 12 propulsion systems; this would take 12p time.  Together it takes 56 hours; this would give us

8c+12p=56

This gives us the system

To solve this, we want the coefficients of one of the variables to be the same.  To make the coefficients of c the same, we can multiply the top equation by 2:

To cancel c, we will subtract the second equation from the first one.  However, this also cancels p:

We get a statement that is not true; thus the system has no solution, and we cannot solve for a unique amount of time.

Step-by-step explanation:

Given :

Machine A ran for 26 hours and produced 4 cockpits and 6 propulsion systems.

Machine B ran for 56 hours and produced 8 cockpits and 12 propulsion systems.

To Find :  Can we solve for a unique amount of time that it takes each machine to produce a cockpit and to produce a propulsion system?

Solution :

Let x be the time taken to produce 1 cockpits

So, time taken to produce 4 cockpits = 4x

So, time taken to produce 8 cockpits = 8x

Let y be the time taken to produce 1 Propulsion

So. time taken to produce 6 propulsion = 6y

So. time taken to produce 12 propulsion = 12y

Now we are given that Machine A ran for 26 hours and produced 4 cockpits and 6 propulsion systems.

⇒  --a

We are also given that Machine B ran for 56 hours and produced 8 cockpits and 12 propulsion systems.

⇒  --b

Solving equation a and b by substitution method

Substitute the value of x from equation in b

⇒

⇒

⇒

We get a statement that is not true; thus the system has no solution, and we cannot solve for a unique amount of time.

i am sorry it just submitted an answer but the answer is 365 boys. hopes this

step-by-step explanation:

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.