Solve the following function for y when x=5 round to the nearest tenth y=13(0.5^x)

In the given question , we have a function given , which is

And we need to find the value of y when x=5.

So we substitute 5 for x and solve for y, that is

And on rounding to the nearest tenths, we will get

So when x=5, y=0.4

3x^3-x^2+6x-9

mental cunning

explanation:

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