If the probability of success during a single event of a geometric experiment is 0.34, what is the probability of success on the 6th event? round your answer to the nearest tenth of a percent. a. 4.3% b. 6.5% c. 2.8% d. 9.8%

Since, the probability of success during a single event of a geometric experiment is 0.34.

We have to find the probability of success on the 6th event.

Since it is a geometric experiment. So, when a discrete random variable 'X' is said to have a geometric distribution then it has a probability density function (p.d.f.) of the form:

P= , where q = 1 - p

So, now

P =

where 'p' is the probability of success and 'q' is the probability of failure and x is the number of events.

Since the probability of success (p)is 0.34

Therefore, probability of failure(q)= 1 - p

= 1 - 0.34

= 0.66

and x = 6

So, P =

=

=

= 0.0425

So, the nearest tenth of a percent of probability of success on the 6th event =

4.257 %

Rounding to the nearest tenth, we get

= 4.3%

So, Option A is the correct answer.

hello from mrbilldoesmath!

answer:

x - 3

discussion:

x^2 - 9 = (x-3) (x+3)   so

(x^2-9)/ (x + 3) = x-3

you,

mrb

d. 8

step-by-step explanation:

the given radical expression is:

we can rewrite this as:

we express as square numbers to get;

the exponents will now cancel out to give.

the correct answer is d