For a resistor in a direct current circuit that does not vary its resistance, the power that a resistor must dissipate is directly proportional ti the square of the voltage across the resistor. the resistor must dissipate 1/16 watt of power when the voltage across the resistor is 14 volts. find the power that the resistor must dissipate when the voltage across it is 42 volts.

THe problem is basically telling us:

where P is the power disappated and V^2 is our voltage squared.

So, for the second example to find the power we simply have to plug k and our voltage back in, so:

36 is the final answer! : )

step-by-step explanation:

12: 00 p.m. to 7: 00 p.m. is a total of 7 hours.

4: 00 p.m. to 7: 00 p.m. is a total of 3 hours.

this means that from 4: 00 p.m to 7: 00 p.m. this represents 3/7 of what was lost from 12: 00 p.m. to 7: 00 p.m.

after knowing this, after doing 11,600 - 6,800 = 4,800

4,800 represents 3/7 of what was lost for 7 hours.

we then divide 4,800 by 3 which gets 1,600.

because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200.   after adding 11,200 to how much water was left at 7: 00 p.m. which was 6,800. 11,200 + 6,800 = 18,000

this means that the pool originally had 18,000 gallons in the pool.

you can also check your work by doing 18,000 - 4(1600), which becomes           1800 - 6400 which gets you 11,600.