If cos theta = 3/5 and theta is in quadrant 4, sin 2 theta =

Hello!

In the first quadrant, all the trigonometric functions are positive.

In the second quadrant, sin and csc are positive, the rest are negative.

In the third quadrant, tan and cot are positive; the rest are negative.

In the fourth quadrant, cos and sec are positive, and the rest are negative.

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To find sin 2θ, we use the equation: sin 2θ = 2 sinθ cosθ.

Since we are given cos θ, which is 3/5, we need to find sin θ.

cos θ = x / r

sin θ = y / r

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To find y, we need to use the Pythagorean Theorem.

3² + y² = 5²

9 + y² = 25 (subtract 9 from both sides)

y² = 16 (take the square root of both sides)

y = 4

Since sin θ is negative in quadrant 4, the y-value of sin θ is negative.

Therefore, sin θ = -4/5.

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Then, we can substitute these values into sin 2θ = 2sinθ cosθ

sin 2θ = 2(-4/5)(3/5)

sin 2θ = (-8/5)(3/5)

sin 2θ = -24/25

Therefore, sin 2 theta is equal to -24/25.

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step-by-step explanation:

we have the parent function given by,

1. the function is translated 5 units to the left.

so, we get,   becomes

2. the function is translated 5 units to the right.

so, we get,   becomes

3. the function is translated 5 units upwards.

so, we get,   becomes

4. the function is translated 5 units downwards.

so, we get,   becomes

5. the function is reflected across x-axis.

so, we get,   becomes

6. the function is reflected across y-axis.

so, we get,   becomes .

step-by-step explanation:

mark brainliest.