Ineed your . i can't solve this problem.

It is pi over 6:

We first solve this by determining how many times it goes around the circle. When you turn 25pi/6 into a mixed number you get 4pi + 1pi/6. Since it takes 2pi to get around the circle once, you go around the circle twice with 4pi. This leaves with 1pi/6 left at the starting point. The answer is pi/6. 13pi/6 also has the same terminal angle but it is not in range of answers (they are asking for 0-2pi)

it 2

step-by-step explanation:

8^1/3=2

the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner is 2.

spinner 1 spinner 2

1                     1

1                     2

1                     3

1                     4

2                   1

2                   2

2                   3

2                   4   = not 1, and 4

3                   1

3                   2

3                   3

3                   4 = not 1, and 4

only 2 outcomes have passed the given condition.

step-by-step explanation: