Write an expression to represent the sum of there consecutive integers the smallest of which in n

Note that they are consecutive (for example: 3,4,5).

The smallest integer is n

your expression will look like:

n + (n + 1) + (n + 2)

hope this helps

b) 1/3 * 1/5

step-by-step explanation:

each smallest part is 1/15 since the written one is 1/5 and it's divided by 3 equal parts. (1/5 )/3 = 1/15 = 1/3 * 1/5

the answer is "add 2y and y"

step-by-step explanation:

you need to collect the like terms first.