Sin^2x/cos^2 + sinxcscx = sec^2x identify it, explain so i know how you did it,

Verify the following identity:

sin(x)^2/cos(x)^2 + sin(x) csc(x) = sec(x)^2

Put csc(x) sin(x) + sin(x)^2/cos(x)^2 over the common denominator cos(x)^2: csc(x) sin(x) + sin(x)^2/cos(x)^2 =

(cos(x)^2 csc(x) sin(x) + sin(x)^2)/cos(x)^2:

(cos(x)^2 csc(x) sin(x) + sin(x)^2)/cos(x)^2 = ^?sec(x)^2

Multiply both sides by cos(x)^2:

cos(x)^2 csc(x) sin(x) + sin(x)^2 = ^?cos(x)^2 sec(x)^2

Write cosecant as 1/sine and secant as 1/cosine:

sin(x)^2 + 1/sin(x) cos(x)^2 sin(x) = ^?cos(x)^2 ( (1/cos(x) )^2 )

cos(x)^2 (1/sin(x)) sin(x) + sin(x)^2 = cos(x)^2 + sin(x)^2:

cos(x)^2 + sin(x)^2 = ^?cos(x)^2 (1/cos(x))^2

cos(x)^2 (1/cos(x))^2 = 1:

cos(x)^2 + sin(x)^2 = ^?1

cos(x)^2 = 1/2 (cos(2 x) + 1):

(cos(2 x) + 1)/2 + sin(x)^2 = ^?1

(cos(2 x) + 1)/2 = 1/2 cos(2 x) + 1/2:

1/2 + (cos(2 x))/2 + sin(x)^2 = ^?1

sin(x)^2 = 1/2 (1 - cos(2 x)):

1/2 + cos(2 x)/2 + (1 - cos(2 x))/2 = ^?1

(1 - cos(2 x))/2 = 1/2 - 1/2 cos(2 x):

1/2 + cos(2 x)/2 + 1/2 - (cos(2 x))/2 = ^?1

1/2 + cos(2 x)/2 + 1/2 - (cos(2 x))/2 = 1:

1 = ^?1

The left hand side and right hand side are identical:

(identity has been verified)

step-by-step explanation: