What are the zeros of the quadratic function f(x) = 8x2 – 16x – 15? x = –1 – and x = –1 + x = –1 – and x = –1 + x = 1 – and x = 1 + x = 1 – and x = 1 +

8x^2 - 16x - 15 = 0

x = [ -(-16) +/- sqrt((-16)^2 - 4*8*-15) / ] 2*8

= 2.696, -0.696

The zeroes of the given polynomial f(x) are

Step-by-step explanation:

Given : Quadratic function

To find : What are the zeros of the quadratic function?

Solution :

Using quadratic formula of the general equation to get the roots is

Comparing the given quadratic equation,

a = 8, b = -16  and  c = - 15.

Substitute the value in the formula,

Therefore, The zeroes of the given polynomial f(x) are

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions