Adult tickets to the fall play cost $8 and student tickets cost $4. the drama class sold 20 more adult tickets than student tickets to the fall play. if the class collected $880 from ticket sales, how many adult tickets were sold?

Hi! Welcome to Let's solve this word problem together below! :)

Let's write this as a system of equations.

8a+4s=880

a= s+20

Let's plug our a value into the first equation.

8(s+20)+4s=880

8s+160+4s=880

We combine like terms.

12s+160=880

We subtract 160 from both sides.

12s=720

We divide both sides by 12

s=60

Now, we plug this value into the second equation.

a= 60+20

a= 80

Therefore, 80 adult tickets were sold.

I hope this helps! Have a fabulous time here at :)

solution:

as, mean is defined as sum of all the observations divided by total number of observations.

and , median is mid value of the data whether arranged in ascending order or descending order.

consider, roadsters:

2,3,4,5,6,7,8,9

mean =

also, median= , because number of observations is even, so median is mean of two mid values.

now, coming to bandits

2,3,4,5,6

mean =  

median = 4, as number of observations is odd.

so, roadsters has greater median as well mean than bandits.

→option a is true about the repairs performed on 2 types of cars:

bandits have lower median and mean than roadsters.

-4

step-by-step explanation:

do 6-10=

if u need it to be negative.