At most, keith can spend $90 on sandwiches and chips for a company lunch. he already bought chips for $15 and will buy sandwiches that cost $6 each. the inequality 15 + 6s ≤ 90 represents the described cost, where s is the maximum number of sandwiches that could be bought. what is the maximum number of sandwiches keith can buy?

It is given in the question that,

At most, Keith can spend $90 on sandwiches and chips for a company lunch. He already bought chips for $15 and will buy sandwiches that cost $6 each. The inequality

represents the described cost, where s is the maximum number of sandwiches that could be bought.

Now we have to solve for s, and for that, we first subtract 15 to both sides, that is

Dividing both sides by 6

So the maximum number of sandwiches Keith can buy is 12.

the multiples of 15 are 15, 30,45, 60, 75, 90, 105, 120, 135, 150, 165, 180, 195,   210, 225, 240, 255, 270, 285, 300, 315, 330, 345, 360, 375,   390, 405, 420, 435, 450, 465, 480, 495, 510, 525, 540, 555, 570, 585, 600, 615, 630, 645, 660, 675, 690, 705, 720, and 735.

the factors of 15 are 1, 3, 5, and 15.

hope that , fam!

-une, your fren : )