Aquarterback is sacked for a loss of 5 yards. on the next day his team loses 15 yards. then the team gains 12 yards on the third play.

Assume it is first down and ten in this problem. When you lose 5 yards on the sack, you are 5 yards further away. So now, it is second and 15. Then, they lose another 15 yards, so it's now third and 30. The final play is that they gain 12 yards, meaning after all the plays it is fourth down and eighteen yards to go.

In math symbols, 0 is where the first down marker is. You start at -10.

First play, the sack: -10 - 5 = -15

Second play: -15 - 15 = -30

Third play: -30 + 12 = -18.

Looks like you have to punt on fourth down :)

the answer is he is sacked so he no longer has a job...

b. 153 students do not participate in sports and seventy-five 12th graders were surveyed

answer: it actually depends on which is the independent variable and which is the dependent variable. let us say we're looking at a linear equation. y=2x+3. we theoretically could switch the equation to be x=(y-3)/2 and it would be the same line. so either a causes b or it can be that b causes a. so technically the answer is false

step-by-step explanation: