Algebra 1, sem. 2 a cannonball is shot straight up into the air. the height of the cannonball at time t is represented by the function f(t)=−16t2+50t+2 . what does the 2 represent? the time when the cannonball hits the ground the maximum height of the cannonball the initial velocity of the cannonball the initial height of the cannonball

The formula is to calculate the overall height of the cannon ball.

the -16T62 is for the force of gravity, the 50t is for the velocity the ball travels, and the +2 is the initial height off the ground.

The answer would be: the initial height of the cannonball.

answer is more than one

step-by-step explanation:

since the airplane is moving with constant speed then the distance travelled can be calculated by x=u*t

in km/h would be:

x=640*3.5=2.240 km

in m/s would be:

u=640 km/h= 640.000 m/h =640.000/ 3600 m/s =177.8 m/s

t= 3.5 h= 3.5 * 3600 s=12.600 s

then x=u*t= 177.8*12.600= 2.240.280 m