Captain calculus can leap over tall buildings. when he does so, his height s (in feet) off the ground after t seconds is given by s(t) = t^2+7t+34. for how many seconds is captain calculus more than 40 feet off the ground?

we are given

height function as

we have to find time at which height is more than 40 feet off the ground

so, we can set up inequality as

now, we can simplify it

Let's assume it is equal to 0

and then we can solve for t

we can use quadratic formula

so,

so, closest value is 1

so, captain calculus more than 40 feet off the ground after 1 seconds.......Answer

2x^2+5x+17

your welcome. : )

-60.75

step-by-step explanation:

just add the numbers then put the negative sign on it