Three consecutive odd integers have a sum of 39. find x, the smallest of the three integers

The three integers are 11, 13, and 15.

Explanation:

We shall consider the integers as x, (x+2), and (x+4). The sum of these is 39, so we can write:

x+(x+2)+(x+4)=39

Open the brackets and simplify.

x+x+2+x+4=39

3x+6=39

Subtract 6 from each side.

3x=33

Divide both sides by 3.

x=11

Therefore: (x+2)=13 and (x+4)=15

hope this helps!

step-by-step explanation:

a cube has 6 sides

the probability of getting 5 on the first cube is 1/6 since only one side of the cube has 5 on it.

there are 3 sides of the cube with even number on it [2,4,6]

therefore the probability of getting even number is 3/6

for both events to happen together, the probability would be

1/6 x 3/6 = 12/36

which simplifies to 1/12