A(x) = 3x+1 and b(x) = square root of x-4, what is the domain of (b•a)(x)

a(x) = 3x + 1

b(x) =

(b . a)(x) =

(b . a)(x) =

We know some things:

There's no square root of a negative number, so,

x - 4 ≥ 0

x ≥ 4

This way, we can say that the domain of (b . a)(x) is:

Dom (b . a)(x) = R ≥ 4

All real numbers higher or equal to 4.

answer: there are 453.592 grams in a pound.

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)