Ebisects df, de=2y, and ef=8y-3. find de, ef, and df

de is congruent to ef definition of bisector

de = ef definition of congruency

2y = 8y - 3 substitution

-6y = -3 subtraction property (subtracted 8y)

y = division property (divided by -6)

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de = 2y = 2( ) = 1

ef = 8y - 3 = 8( ) - 3 = 4 - 3 = 1

de + ef = df segment addition postulate

1 + 1 = df substitution

2 = df simplify

de=1, ef=1, df=2

step-by-step explanation:

hjkj

4 candies

step-by-step explanation:

7 x 28 = 196

200 - 196 = 4 candies remaining.