Alibrary subscribes to two different weekly news magazines, each of which is supposed to arrive in wednesday's mail. in actuality, each one may arrive on wednesday, thursday, friday, or saturday. suppose the two arrive independently of one another, and for each one p(wed.) = 0.29, p(thurs.) = 0.37, p(fri.) = 0.16, and p(sat.) = 0.18. let y = the number of days beyond wednesday that it takes for both magazines to arrive (so possible y values are 0, 1, 2, or 3). compute the pmf of y. [hint: there are 16 possible outcomes; y(w, w) = 0, y(f, th) = 2, and so on.]

p(0) = p(w,w) = 0.29² = 0.0841

p(1) = p(t, w+t) + p(w, t) = 2p(w,t) +p(t,t) = 2·.29·.37 + .37² = 0.3515

p(2) = p(f, w+t+f) +p(w+t, f) = 0.16(2(.29+.37)+.16) = 0.2368

p(3) = p(s, w+t+f+s) +p(w+t+f, s) = 0.18(2(.29+.37+.16) +.18) = 0.3276

In summary, your pmf is ...

y : p(y)

0 : 0.0841

1 : 0.3515

2 : 0.2368

3 : 0.3276

y=mx+b

step-by-step explanation:

m is slope, b is y-intercept

find the magnitude of the trig term  

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by taking the absolute value of the coefficient.

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find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

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the range is  

y

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or  

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≥

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(

−

∞

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{

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step-by-step explanation: