Mathematics, 12.07.2019 11:00 pwolfiimp4
Find the equation of the line that passes through (-2,5) and is perpendicular to the line passing through (-6,1/2) and (-4,2/3). write the equation in slope intercept form.
Answers: 1
![\bf (\stackrel{x_1}{-6}~,~\stackrel{y_1}{\frac{1}{2}})\qquad (\stackrel{x_2}{-4}~,~\stackrel{y_2}{\frac{2}{3}}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{~~\frac{2}{3}-\frac{1}{2}~~}{-4-(-6)}\implies \cfrac{~~\frac{4-3}{6}~~}{-4+6} \\\\\\ \cfrac{~~\frac{1}{6}~~}{2}\implies \cfrac{~~\frac{1}{6}~~}{\frac{2}{1}}\implies \cfrac{1}{6}\cdot \cfrac{1}{2}\implies \boxed{\cfrac{1}{12} } \\\\[-0.35em] ~\dotfill](/tpl/images/0080/6841/5ddd3.png)
![\bf (\stackrel{x_1}{-2}~,~\stackrel{y_1}{5})~\hspace{7em} slope = m\implies -12 \\\\\\ \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-5=-12[x-(-2)] \\\\\\ y-5=-12(x+2)\implies y-5=-12x-24\implies \blacktriangleright y=-12x-19 \blacktriangleleft](/tpl/images/0080/6841/9a636.png)
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