The distribution of the amount of money spent by first-time gamblers at a major casino in las vegas is approximately normal in shape with a mean of 600 a n d a s t a n d a r d d e v i a t i o n o f 120. according to the standard deviation rule, almost 84% of gamblers spent more than what amount of money at this casino?

Solution: We are given:

We need to find the z value corresponding to probability 0.84, in order to find the how much money almost 84% of gamblers spent at casino.

Using the standard normal table, we have:

Now we will use the z score formula to find the required amount:

approximately

Therefore, almost 84% of gamblers spent more than $720 amount of money at this casino.

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

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y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation:

answer:

step-by-step explanation: