Answers: 2
![\bf (\stackrel{x_1}{2}~,~\stackrel{y_1}{3})\qquad (\stackrel{x_2}{-3}~,~\stackrel{y_2}{2})\\\\\\slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{2-3}{-3-2}\implies \cfrac{-1}{-5}\implies \cfrac{1}{5}\\\\[-0.35em]\rule{34em}{0.25pt}](/tpl/images/0080/1095/fc9ca.png)
![\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{-3})~\hspace{10em} slope = m\implies -5 \\\\\\ \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-3)=-5(x-3) \\\\\\ y+3=-5x+15\implies y=-5x+12 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{x=2}{y=-5(2)+12}\implies y=-10+12\implies y=2~\hfill \boxed{(2,2)}](/tpl/images/0080/1095/35777.png)
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Perpendicular to mn and passes through point k...
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