Will mark brainliest evaluate the expression for the given value of the variable. |-4b-8|+|-1-b^2|+2b^3 ; b=-2 show all work

Evaluate abs(-4 b - 8) + abs(-b^2 - 1) + 2 b^3 where b = -2:

abs(-4 b - 8) + abs(-b^2 - 1) + 2 b^3 = abs(-4 (-2) - 8) + abs(-1 - (-2)^2) + (-2)^3×2

(-2)^2 = 4:

abs(-4 (-2) - 8) + abs(-4 - 1) + 2×(-2)^3

-4 (-2) = 8:

abs(8 - 8) + abs(-4 - 1) + 2×(-2)^3

8 - 8 = 0:

abs(0) + abs(-1 - 4) + 2×(-2)^3

-1 - 4 = -5:

abs(0) + abs(-5) + 2×(-2)^3

(-2)^3 = (-1)^3×2^3 = -2^3:

abs(0) + abs(-5) + 2×-2^3

2^3 = 2×2^2:

abs(0) + abs(-5) + 2 (-2×2^2)

2^2 = 4:

abs(0) + abs(-5) + 2 (-2×4)

2×4 = 8:

abs(0) + abs(-5) + 2 (-8)

Since 0 is at the origin, then abs(0) = 0:

abs(-5) - 8×2

Since -5<=0, then abs(-5) = 5:

5 - 8×2

2 (-8) = -16:

-16 + 5

5 - 16 = -11:

-11

step-by-step explanation:

i found the life tables for the year 2012. 

life table of males at age 30. probability of dying between ages x and x+1

total population:  

29–30 . . . . . . . . . . . . 0.001030

30–31 . . . . . . . . . . . . 0.001061

males:  

29–30 . . . . . . . . . . . . 0.001420

30–31 . . . . . . . . . . . . 0.001448

white population

29–30 . . . . . . . . . . . . 0.001005

30–31 . . . . . . . . . . . . 0.001037

white males

29–30 . . . . . . . . . . . . 0.001372

30–31 . . . . . . . . . . . . 0.001399

non hispanic white population

29–30 . . . . . . . . . . . . 0.001083

30–31 . . . . . . . . . . . . 0.001116

non hispanic white males

29–30 . . . . . . . . . . . . 0.001477

30–31 . . . . . . . . . . . . 0.001503

jacob, non hispanic white male. 30 years old.

probability that jacob lives to be 30 years old. 

since the given probabilities are probabilities of dying, i think we simply subtract it from 1 to get the probability of living. we will use the probability of non hispanic white male.

                                          probability of living to be 30 y.o.

29 - 30 : 1 - 0.001477 = 0.998523

30 - 31 : 1 - 0.001503 = 0.998497

"image"

step-by-step explanation:

in most of these problems, the notation is that the point with a "prime" is the image of the point without. that is, b' is the image of b.

here, there is no dilation or reflection. there is simply translation (with no direction shown). which figure you call the "preimage" and which one you call the "image" is up to you. as a matter of convention, the naming is as described above.