Pq=2x-3. if qr=5x+7 and pr=10x-11, then pr=?

Given: PQ=2x-3. if QR=5x+7 and PR=10x-11

To Find: PR

Solution: From the attached diagram, point P, Q and R are co-linear.

Hence,       PR = PQ + QR

or,         10x-11 = 2x-3 + 5x+7

or,      10x - 7x = 15

or,                 x = 5

Now, we shall calculate the value of PR

                 PR = 10x-11

or,              PR = 10× 5 - 11

or,              PR = 39

Hence, the required value of PR will be 39.

answer: 1000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000

step-by-step explanation:

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11