Solve the system of equations below by graphing both equations with a pencil and paper. what is the solution? y=x-1 y=1/2x+1 ,-3) b.(4,3) c.(2,1) ,0)

The graph doesn't have to be very sophisticated to come to the correct choice of those offered. Both lines have positive slope, and the one with the least slope has a positive y-intercept. The solution must be in the first quadrant, and must have a y-value greater than 1.

The appropriate choice is

... B. (4, 3)

Option B is correct.

Step-by-step explanation:

Given Equation of lines are

y = x - 1 ...................(1)

y = 1/2x + 1 ...............(2)

To draw them on line, we find two points or solution of line.

Consider, line 1

put x = 0                                    

we get, y = 0 - 1 = -1                

Now, put x = 1

we get, y = 1 - 1 = 0  

So the required point of line 1 are ( 0 , -1 )  and ( 1 , 0 )

Consider, line 2

put x = 0                                    

we get, y = 0 + 1 = 1                

Now, put x = -2

we get, y = -1 + 1 = 0  

So the required point of line 2 are ( 0 , 1 )  and ( -2 , 0 )

Now we graph graph using obtained point.

Graph is attached.

Clearly from the graph, Point of intersection is ( 4 , 3 )

Therefore, Option B is correct.

i'm not entirely sure

step-by-step explanation:

if you ask home depot or lowe's they might be able to you out

answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.