If there are 4 more nickels in a jar than there are dimes, which could be the ratio of dimes to nickels in the jar? a. 8/10b. 1c.14/10d. 4e. none of the abovei really need

Let number of nickels be n

and number of dimes be d

we know that there are 4 more nickels than there are dimes

⇒ n = d + 4

We have to find out ratio of d and n

Now, let's substitute the values of each of the option to see whether the values we obtain for d and n are positive or not

(A) 8/10

⇒ \frac{d}{d+4}[/tex] = 8 / 10

⇒ 10 × d = 8 × d + 32

⇒ 2 × d = 32

⇒ d = 16

Hence, n = d+4 = 20. Since n and d are positive values. A is the correct answer

Nevertheless, let's take a look at the other options as well

(B) 1

⇒ \frac{d}{d+4}[/tex] = 1

⇒ d = d + 4

This equation can't be solved since we would be left with 0=4, which doesn't hold true, So B is not the correct answer

(C) 14/10

⇒ \frac{d}{d+4}[/tex] = 14 / 10

⇒ 10 × d = 14 × d + 56

⇒ -4 × d = 56

⇒ d = -16

Since d is negative, it can't represent the number of dimes. So C is not the correct answer.

(D) 4

⇒ \frac{d}{d+4}[/tex] = 4

⇒ d = 4 × d + 16

⇒ d = (-16/3)

Since d is negative, it can't represent the number of dimes. So D is not the correct answer.

(E) None of the above

This is not the correct answer as we have already seen that A is the correct answer.

step-by-step explanation: