F(x) = square root of quantity x plus nine.; g(x) = 8x - 13 find f(g( f(g(x)) = 2square root of quantity two x minus one. f(g(x)) = 8square root of quantity x minus four. f(g(x)) = 2square root of quantity two x plus one. f(g(x)) = 8square root of quantity x plus nine. - 13

Step-by-step explanation:

f(x) = Square root of quantity x plus nine.

Mathematically we can write this as:

We have to find

So, we have to replace x in f(x) with : 8x-13.

=

=

=

=

Hence, answer is : f(g(x)) = 2 Square root of quantity two x minus one.

you would use (d.) the law of cosines or a^2 = b^2 + c^2 – 2bc(cos a)

, b^2 = a^2 + c^2 – 2ac(cos b), or c^2 = a^2 + b^2 - 2ab(cos c). you wouldn't use b. the law of sines as it is mostly effective when 1side and 2angles are given. a and c aren't the answer for they are the improper versions of the law of cosines. hope this is .